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The impedance of the last two elements in the parallel combination after transformation in the circuit shown below is?(a) 1/(s+4)(b) 1/(s+3)(c) 1/(s+2)(d) 1/(s+1)I have been asked this question in an interview for internship.Origin of the question is Series and Parallel Combination of Elements topic in division S-Domain Analysis of Network Theory

Answer»

The correct CHOICE is (a) 1/(s+4)

Easiest explanation: The impedance of RESISTOR is 4Ω and the impedance of CAPACITOR is s. So the impedance of the last two elements in the PARALLEL combination is Z1(s) = 1/(s+4).



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