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The impedance seen by the source in the circuit is given by __________(a) (0.54 + j0.313) Ω(b) (4 – j2) Ω(c) (4.54 – j1.69) Ω(d) (4 + j2) ΩI got this question at a job interview.My doubt is from Advanced Problems on Magnetically Coupled Circuits topic in portion Resonance & Magnetically Coupled Circuit of Network Theory

Answer» CORRECT choice is (C) (4.54 – j1.69) Ω

For EXPLANATION: Z1 = 10∠30° × (\(\frac{1}{4}\))^2

Z1 = (0.54 + j0.31) Ω

Total impedance= (4 – j2) + (0.56 + j0.31)

= (4.54 – j1.69) Ω.


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