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The ionic strength of a solution containing `0.1"mole"//kg` of KCI and `0.2"mole"//kg` of `CuSO_(4)` isA. 0.3B. 0.6C. 0.9D. 0.2 |
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Answer» Correct Answer - C Ionic strength is half of the sum of all the terms obtained by multiplying the molality of each ion by the square of its valency. `1 = (1)/(2) (m_(1)z_(1)^(2) +m_(2)z_(2)^(2)+m_(3)z_(3)^(2)+m_(4)z_(4)^(2))` Here for `K^(+)` ion, `m_(1) = 0.1 m, z_(1) = 1` For `CI^(-)` ion, `m_(2) = 0.1m, z_(2) = 1` For `Cu^(2+)` ion, `m_(3) = 0.2m, z_(3) = 2` For `SO_(4)^(2-)` ion `m_(4) = 0.2 m, z_(4) = 2` `:. 1 =(1)/(2)[0.1 xx 1^(2) +0.1 xx 1^(2) +0.2 xx 2^(2) +0.2 xx 2^(2)]` `= (1)/(2) [0.1 +0.1 +0.8 +0.8]` `= (1.8)/(2) = 0.9` |
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