1.

The ionisation energy of `He^(o+)` is `19.6 xx 10^(-18) J atom^(-1)` .The energy of the first stationary state of `Li^(2+)` will beA. `84.2 xx 10^(-18) J" atom" ^(-1)`B. `84.10 xx 10^(-18) J "atom" ^(-1)`C. `63.2 xx 10^(-18) J "atom" ^(-1)`D. `21.2 xx 10^(-18 J) "atom" ^(-1)`

Answer» `E_(1)` "for"` Li^(2+) = E_(1) for H xx Z^(2)for H xx 4`
E_(1)`" for" `He^(o+) = E_(1) xx Z_(He)^(2)= E_(1)"for" H xx 4`
or `E_(1)" for" Li^(2+) = (9)/(4) E_(1) for He^(o+) = 19.6 xx 10^(-16) xx (9)/(4) = 44.10 xx 10^(-19) J" atom"^(-1)`


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