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The ionisation energy of `He^(o+)` is `19.6 xx 10^(-19) J "atom"^(-1)`. Calculate the energy of the first stationary state of `Li^(2+)` |
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Answer» Correct Answer - A::B::D IE of an ion = IE of H atom `xx Z^(2)` IE of H atom = `(IE of an ion)/(Z^(2))= (IE of an He^(o+))/(Z^(2))` `= (19.6 xx 10^(-18))/(4) J = 4.9 xx 10^(-18) J` `IE of Li^(2+) = 4.9 xx 10^(-18) J xx 3^(2) = 4.41 xx 10^(-17) J` |
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