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The ionisation energy of `He^(o+) is `19.6 xx 10^(-19) J "atom "^(-1)` .Calculate the energy of the first stationary state of `li^(2+)` |
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Answer» `E_(1)` for `Li^(2+) = E_(1)` for `H xx Z^(2) = E_(1)` for `H xx 9` `E_(1)` for `He^(o+) = E_(1)` for `H xx Z^(2) = E_(1)` for `H xx 4` ` :. E_(1)` for` Li^(2+) = E_(1)` for `He^(o+) xx (9)/(4)` `19.6 xx 10^(-19) xx (9)/(4)` `= 44.1 xx 10^(-19) J "atom"^(-1)` |
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