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The ionization energy of the ground state of hydrogen atom is `2.18 xx 10^(-8)J`. The energy of an electron in its second orbit would beA. `-1.09 xx 10^(-18)J`B. `-2.18 xx 10^(-18)J`C. `-4.36 xx 10^(-18)J`D. `-5.45 xx 10^(-19)J` |
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Answer» Correct Answer - D `E_(n) = (-E_(1))/(n^(2))` |
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