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The isotope `._(92)U^(238)` successively undergoes eight `alpha`-decays and six `beta`-decays. The resulting isotope is found to be `._(92-5y)X^(238-4x)`. Find the value of ratio `x//y`. |
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Answer» Correct Answer - 4 `._(92)U^(238)overset( 8alpha+6 beta)rarr_(82)Pb^(206)` |
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