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The `KE` and `PE` , at is a particle executing `SHM` amplitude `A` will be equal when its displacement isA. `Asqrt(2)`B. `A//2`C. `A//sqrt(2)`D. `Asqrt(2//3)` |
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Answer» Correct Answer - C `K = (1)/(2) m omega ^(2)(A^(2)- y^(2))` `U = (1)/(2) m omega^(2)y^(2)` `K = U` or `(1)/(2) m omega^(2) (A^(2) - y^(2)) = (1)/(2) m omega^(2) y^(2)` `i.e. 2y^(2) = A^(2)` or `y = (A)/(sqrt(2))` |
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