1.

The `KE` and `PE` , at is a particle executing `SHM` amplitude `A` will be equal when its displacement isA. `Asqrt(2)`B. `A//2`C. `A//sqrt(2)`D. `Asqrt(2//3)`

Answer» Correct Answer - C
`K = (1)/(2) m omega ^(2)(A^(2)- y^(2))`
`U = (1)/(2) m omega^(2)y^(2)`
`K = U` or `(1)/(2) m omega^(2) (A^(2) - y^(2)) = (1)/(2) m omega^(2) y^(2)`
`i.e. 2y^(2) = A^(2)` or `y = (A)/(sqrt(2))`


Discussion

No Comment Found

Related InterviewSolutions