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The kinetic energy of an electron accelerated from rest through a potential difference of 5V will beA. `5J`B. `5erg`C. `5eV`D. `8 xx 10^(-10)eV` |
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Answer» Correct Answer - C `(1)/(2)mv^(2) = ev, V^(2) = (2eV)/(m), V = sqrt((2eV)/(m))` |
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