1.

The kinetic energy of an electron is `4.55 xx 10^(-25) J` .The mass of electron is `9.1 xx 10^(-34) kg` Calculate velocity of the electron

Answer» Calculate of the electron
Kinetic energy `= (1)/(2) mv^(2) = 4.55 xx 10^(-25) J = 4.55 xx 10^(-25) kg m^(2)s^(-2)`
or `v^(2) = (2 xx KE)/( m) = (2 xx (4.55 xx 10^(-25) kg m^(2)s^(-2) J))/((9.1 xx 10^(-31) kg))`
`= 10^(6) m^(2)s^(-2)`
or Velocity (v) = `(10^(4)m^(2)s^(-2))^((1)/(2)) = 10^(3) m s^(-1)`


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