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The least integral value of `x`where `f(x)=(log)_(1/2)(x^2-2x-3)`is monotonically decreasing is________ |
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Answer» Correct Answer - 4 `x^(2)-2x3gt0` or `(x-3)(x+1)gt0` i.e `xlt1 or xgt3` Now `f(X)=log_(1//2)(x^(2)-2x-3)` `=log_(e)(x^(2)-2x-3)/(log_(e)(1//2))` `f(X)=(2x-2)/(log_(e)(1//2))(x^(2)-2x-3)` For f(x) to decreasing `f(X)lt0` or `(x-1)/(log_(e)(1//2)(x-3)(x+1))lt0` or `xgt1` From 1 and 2 x `gt`3 |
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