1.

The least value of 3cos2α + 4sin2 α is:1). –32). 33). –44). 4

Answer»

3 cos2α + 4 sin2 α = 3 cos2α + 4 (1 – cos2 α) = 4 – cos2 α

The minimum value occurs when cos α = 1

So minimum value is = 4 – 1 = 3


Discussion

No Comment Found

Related InterviewSolutions