The length of a smooth inclined plane of 30-degree inclination is 5 m. The work done in moving a 10 kg mass from the bottom of the inclined plane to the top is _____ Joules. (Assume g = 10m/s^2)(a) 250(b) 1000(c) 1250(d) 500I got this question in examination.My doubt is from Work Done by a Variable Force topic in section Work, Energy and Power of Physics – Class 11

The length of a smooth inclined plane of 30-degree inclination is 5 m.

1.	The length of a smooth inclined plane of 30-degree inclination is 5 m. The work done in moving a 10 kg mass from the bottom of the inclined plane to the top is _____ Joules. (Assume g = 10m/s^2)(a) 250(b) 1000(c) 1250(d) 500I got this question in examination.My doubt is from Work Done by a Variable Force topic in section Work, Energy and Power of Physics – Class 11
Answer» The correct ANSWER is (a) 250 Explanation: Length (l) = 5 m Height = DISPLACEMENT = 5 x sin30 = 5 x (1/2) = 2.5 Force on object = m x G = 10 X 10 = 100 N Work = Force x Displacement = 100 x 2.5 = 250 Joules.

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