1.

The length of the perpendicular from the origin to a line is 7, and the line makes an angle of 150° with the positive direction of y–axis. Find the equation of the line.

Answer»

AB be the given line which makes an angle of 150° with the positive direction of y–axis and OQ be the perpendicular drawn from the origin on the line. 

Given:

p = 7 and α = 30° 

Explanation: 

So, the equation of the line AB is 

Formula Used: x cos α + y sin α = p 

⇒ x cos 30° + y sin 30° = 7

⇒ \(\frac{\sqrt{3x}}{2}+\frac{y}{2}\)

⇒ √3 x + y = 14 

Hence, the equation of line in normal form is √3 x + y = 14



Discussion

No Comment Found