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The length of the perpendicular from the origin to a line is 7, and the line makes an angle of 150° with the positive direction of y–axis. Find the equation of the line. |
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Answer» AB be the given line which makes an angle of 150° with the positive direction of y–axis and OQ be the perpendicular drawn from the origin on the line. Given: p = 7 and α = 30° Explanation: So, the equation of the line AB is Formula Used: x cos α + y sin α = p ⇒ x cos 30° + y sin 30° = 7 ⇒ \(\frac{\sqrt{3x}}{2}+\frac{y}{2}\) ⇒ √3 x + y = 14 Hence, the equation of line in normal form is √3 x + y = 14 |
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