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The line `2y=3x+12` cuts the parabola `4y=3x^(2)`. What ishte eccentricity of rectangular hyper bola ?A. `sqrt2`B. `sqrt3`C. `sqrt5`D. `sqrt6` |
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Answer» Correct Answer - A Here, `b^(2)=a^(2)(e^(2)-1)` For rectangular hyperbola : a = b `rArrb^(2)=b^(2)(e^(2)-1)` `rArr" "e^(2)-1=1` `rArr" "e^(2)=2rArre=+-sqrt2` `"For hyperbola, "egt1`. Hence, `e=sqrt2` |
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