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The line `2y=3x+12` cuts the parabola `4y=3x^(2)`. Where does the line cut the parabola ?A. `At(-2, 3)` onlyB. At (4, 12) onlyC. At both (-2, 3) and (4, 12)D. Neither at (-2, 3) nor (4, 12) |
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Answer» Correct Answer - C Equation of line `2y=3x+12" ..(1)"` Equation of parabola `4y=3x^(2)" …(2)"` From eqs. (i) and (ii), we get `2(3x+12)=3x^(2)` `3x^(2)-6x-24=0` `x^(2)-2x-8=0` `(x-4)(x+2)=0` `:." "x=4` `" and "x = -2` Now putting the value of x in eqn (ii) We get y = 12 and y = 3 Thus, the points (-2, 3) and (4, 12) |
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