1.

The line `2y=3x+12` cuts the parabola `4y=3x^(2)`. Where does the line cut the parabola ?A. `At(-2, 3)` onlyB. At (4, 12) onlyC. At both (-2, 3) and (4, 12)D. Neither at (-2, 3) nor (4, 12)

Answer» Correct Answer - C
Equation of line
`2y=3x+12" ..(1)"`
Equation of parabola
`4y=3x^(2)" …(2)"`
From eqs. (i) and (ii), we get
`2(3x+12)=3x^(2)`
`3x^(2)-6x-24=0`
`x^(2)-2x-8=0`
`(x-4)(x+2)=0`
`:." "x=4`
`" and "x = -2`
Now putting the value of x in eqn (ii)
We get y = 12 and y = 3
Thus, the points (-2, 3) and (4, 12)


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