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The longest wavelength of ` He^(+)` in paschen series is "m", then shortest wavelenght of `Be^(+3)` in Pacchen series is( in terms of m):A. `(5)/(36)m`B. `(64)/(7)m`C. `(53)/(8)m`D. `(7)/(64)m` |
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Answer» Correct Answer - D `(1)/(lambda_("longest"))`=`(1)/(m_(e))`=`RZ^(2)((1)/(3^(2))-(1)/(4^2))`=`(7Rxx4)/(16xx9)=(7)/(36)R` `(1)/(lambda_("longest"))`=`RZ^(2)((1)/(3^(2)))`=`(4R)/(9)` `(lambda_("longest"))`=`(7)/(64)m` |
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