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The lower part of a tent isa right circular cylinder of radius14 metres and itsupper part is a right circular cone . If the height of the cylindrical part is 3 metre and the total height of theper square- metre |
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Answer» Solution :The radius of the CYLINDRICAL part = 14 m and the height of this part = 3 m ` :.` the curved SURFACE area of thecylindrical part ` = 2 xx 22/7 xx 14 xx 3 `, = 264 square - metre Again , the height of the CONICAL part OFTHE tent` = (13.5 -3) ` m = 10.5 m and the radius of base = 14 metre ` :. ` the slant height of the conical part ` = sqrt((14)^(2) + (10.5)^(2))`metre ` = sqrt(196 + 110.25 )`metre, ` = sqrt(306.250)` metre = 17.5metre ` :.` the curved surface area of the conical part of the tent ` = 22/7 xx 14 xx 17.5 ` sq - metre = 770 square - metre `:.` the areaof the part of the tent which is to be coloured = `(770+64) `square - metre = 1034 square - metre So the expenditure of COLOURING` = Rs 2 xx 1034` = Rs 2068 Hence the required expenditure = Rs 2068
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