1.

The lower part of a tent isa right circular cylinder of radius14 metres and itsupper part is a right circular cone . If the height of the cylindrical part is 3 metre and the total height of theper square- metre

Answer»

Solution :The radius of the CYLINDRICAL part = 14 m and the height of this part = 3 m
` :.` the curved SURFACE area of thecylindrical part ` = 2 xx 22/7 xx 14 xx 3 `,
= 264 square - metre
Again , the height of the CONICAL part OFTHE tent` = (13.5 -3) ` m
= 10.5 m
and the radius of base = 14 metre
` :. ` the slant height of the conical part
` = sqrt((14)^(2) + (10.5)^(2))`metre
` = sqrt(196 + 110.25 )`metre,
` = sqrt(306.250)` metre
= 17.5metre
` :.` the curved surface area of the conical
part of the tent ` = 22/7 xx 14 xx 17.5 ` sq - metre
= 770 square - metre
`:.` the areaof the part of the tent which is to be coloured = `(770+64) `square - metre
= 1034 square - metre
So the expenditure of COLOURING` = Rs 2 xx 1034`
= Rs 2068
Hence the required expenditure = Rs 2068


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