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The marks obtained (out of 100) by a class of 80 students are given below |
Answer» Solution :In the GIVEN frequency distribution, class sizes are different. So, we calculate the adjusted frequency for each class, Here, minimum size=20-10=10 We use the formula, Adjusted frequency of a class = `("Minimum class size")/("Class size of this class") xx "its frequency"` The modified table for frequency distribution is given below. ![]() Along the HORIZONTAL axis, we represent the class intervls marks on some suitable scale. The corresponding frequencies of number of students are represented along the vertical axis on a suitable scale. Since, the given intervals start with 10-20. It means that, there is some BREAK INDICATED near the origin to slightly the graph is drawn with a scale beginning at 10. Now, we draw rectangles with class intervals as the bases and the corresponding adjusted frequencies as heights. A histogram of the given distribution is given below. ![]() |
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