1.

The molal boiling point constant of water is `0.573^(@)C kg "mole"^(-1)`. When `0.1` mole of glucose is dissolved in `1000g` of water, the solution boils under atmospheric pressure at:A. `100.513^(@)C`B. `100.0573^(@)C`C. `100.256^(@)C`D. `101.025^(@)C`

Answer» Correct Answer - B
`T - 100 = 0.573 xx 0.1`
`T = 100.0573`


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