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The molal boiling point constant of water is `0.573^(@)C kg "mole"^(-1)`. When `0.1` mole of glucose is dissolved in `1000g` of water, the solution boils under atmospheric pressure at:A. `100.513^(@)C`B. `100.0573^(@)C`C. `100.256^(@)C`D. `101.025^(@)C` |
Answer» Correct Answer - B `T - 100 = 0.573 xx 0.1` `T = 100.0573` |
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