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The molality of 3M solution os mehtanol if the density of the solution is `0.9g cm^(-3)`, isA. 3.73B. `3.0`C. 3.33D. 3.1 |
Answer» Correct Answer - a `"Volume of the solution="1 L or 1000 cm^(3)` `"Mass of the solution "=vxxd ` `= (1000cm(3)) xx (0.9 g cm^(3))=900 g` `"Mass of methanol"(CH_(3)OH)=(3 molxx32 "g mol"^(-1))=96 g` `"Mass of solvent" =(900-96g)=804 g=0.804 kg ` `"Molality of solution"=("No. of moles of methanol")/("Mass of solvent in kg")` `(3mol)/(0.804kg)=0.373"mol kg"^(-1)` =.373 molal |
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