1.

The molality of a solution containing 1.8 g of glucose dissolved in 250 g of water is …(a) 0.2 M (b) 0.01 M(c) 0.02 M (d) 0.04 M

Answer»

(d) 0.04 M

Molality = (Number of moles of solute) / (Weight of solvent (in kg) 

= (1.8/180) / 0.25

= 0.01 / 0.25

= 0.04 M



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