InterviewSolution
Saved Bookmarks
| 1. |
The molality of a solution containing 1.8 g of glucose dissolved in 250 g of water is …(a) 0.2 M (b) 0.01 M(c) 0.02 M (d) 0.04 M |
|
Answer» (d) 0.04 M Molality = (Number of moles of solute) / (Weight of solvent (in kg) = (1.8/180) / 0.25 = 0.01 / 0.25 = 0.04 M |
|