1.

The molarity of 98% by wt. `H_(2)SO_(4)` (d = 1.8 g/ml) isA. 6MB. 18MC. 10MD. 4M

Answer» Correct Answer - B
`98% H_(2)SO_(4)` by weight
`rArr 98 g` of `H_(2)SO_(4)` in 100 g of solution
volume of solution `=(100g)/(1.8 g mL^(-1))=55.55 mL`
`=0.056 L`
Moles of `H_(2)SO_(4)=98//98=1 mol`
Molarity `=(1 mol)/(0.056L) = 17.86 M`


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