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The molarity of a solution obtained by mixing 750 mL of 0.5dsM solution of HCI with 250 mL of 2M solution of HCI will be :A. 1.75 MB. 0.975 MC. 0.875 MD. 1.00 M |
Answer» Correct Answer - c `M_(3)V_(3)=M_(1)V_(1)+M_(2)V_(2)` `M_(3)=((0.5M)xx(750mL)+(250 mL))/((750 mL+250 mL))` 0.875 M. |
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