1.

The molarity of a solution obtained by mixing 750 mL of 0.5dsM solution of HCI with 250 mL of 2M solution of HCI will be :A. 1.75 MB. 0.975 MC. 0.875 MD. 1.00 M

Answer» Correct Answer - c
`M_(3)V_(3)=M_(1)V_(1)+M_(2)V_(2)`
`M_(3)=((0.5M)xx(750mL)+(250 mL))/((750 mL+250 mL))`
0.875 M.


Discussion

No Comment Found

Related InterviewSolutions