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The mole fraction of a solute in a solutions is `0.1`. At `298K` molarity of this solution is the same as its molality. Density of this solution at 298 K is `2.0 g cm^(-3)`. The ratio of the molecular weights of the solute and solvent, `(MW_("solute"))/(MW_("solvent"))` is |
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Answer» Correct Answer - 9 When `M = m` `(w_(B)xx1000)/(m_(B)xxV)=(w_(B)xx1000)/(m_(B)xxw_(A))` i.e., `V=w_(A)` Volume of solution = Mass of solvent `("Mass of solution")/("Density")=` Mass of solvent `(w_(A)+w_(B))/(2)=w_(B)` `w_(A)=w_(B)` `x_(A)xxm_(A)=x_(B)xxm_(B)` `0.9xxm_(A)=0.1xxm_(B)` `(m_(B))/(m_(A))=9` `(MW_("solute"))/(MW_("solvent"))=9`] |
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