1.

The moment of inertia of a body moving with angular velocity `omega` decreases from `l` to `(l)/(3)` without any external torque. Calculate the new angular velocity of the body.

Answer» `I_(1)omega_(1)=I_(2)omega_(2)`
`omega_(2)=(I_(1)omega_(1))/(I_(2))=(Iomega)/((I)/(3)))=3omgea`
Hint : `I_(1)omega_(1)=I_(2)omega_(2)`


Discussion

No Comment Found

Related InterviewSolutions