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The moment of inertia of a ring about one of it's diameter is I. What will be the moment of inertia about a tangent parallel to the diameter? |
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Answer» Solution :`I_(T) =I + MR^(2) =1/2mR^(2) + mR^(2)` `=3 XX 1/2 mR^(2)=3I` |
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