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The moment of inertia of a uniform ring about an axis passing through its centre and perpendicular to its plane is `100kgm^(2)`. What is the moment of inertia of the ring about its diameter ? |
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Answer» Moment of inertia of the ring through `CM=100kgm^(2)` `MR^(2)=100` `I` about diameter `=(MR^(2))/(2)=50kgm^(2)` |
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