1.

The moment of inertia of a uniform ring about an axis passing through its centre and perpendicular to its plane is `100kgm^(2)`. What is the moment of inertia of the ring about its diameter ?

Answer» Moment of inertia of the ring through `CM=100kgm^(2)`
`MR^(2)=100`
`I` about diameter `=(MR^(2))/(2)=50kgm^(2)`


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