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The normal boiling point of toluene is `110.7^(@)C` and its boiling point elevation constant `3.32 " K kg mol"^(-1)`. The enthalpy of vaporization of toluene is nearly :A. `"17 kJ mol"^(-1)`B. `"21 kJ mol"^(-1)`C. `"51 kJ mol"^(-1)`D. `"68 kJ mol"^(-1)` |
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Answer» Correct Answer - B `K_(b)=(RT_(0)^(2))/(1000L),3.32=((8.314xx10^(-3))xx(383.7)^(2))/(1000xxL)` `L=0.368kJ//g` Latent heat per mol `= 0.368 xx` molar mass of acetone `= 0.368xx58=21.344" kJ mol"^(-1)`]. |
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