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The nuclear reaction `.^2H+.^2H rarr .^4 He` (mass of deuteron `= 2.0141 a.m.u` and mass of `He = 4.0024 a.m.u`) isA. Fusion reaction releasing `24 MeV` energyB. Fusion reaction absorbing `24 MeV` energyC. Fission reaction releasing `0.0258 MeV` energyD. Fission reaction absoring `0.0258 MeV` energy |
Answer» Correct Answer - A (a) Total mass of reactions =`(2.0141) xx 2 = 4.0282` amu Total mass of products `= 4.0024 `amu Mass defect `= 4.0282 "amu" - 4.0024 "amu"` =`0.0258` amu `:.` Energy released `E = 931 xx 0.0258 = 24 MeV`. |
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