InterviewSolution
Saved Bookmarks
| 1. |
The number fo electrons present in ` 1 cm^3 ` of ` Mg` (density of `. _(12)Mg^(24) g cm^(-3))` is:A. `5 . 24 xx 10^(23)`B. ` 4 lambda//3`C. `3 lambda`D. `3 lambda//4` |
|
Answer» Correct Answer - A `w_(Mg) 1 cm^3 = 1. 74 g` ` :.` No . Of elecrron `= ( 1. 74 xx 12 xx 6.023 xx 10^(23))/(24)` ` = 5.24 . xx 10^(23)`. |
|