The number of `alpha-` particles emitted per second by `1g` of `Ra^(226)` is `3.7 xx 10^(10)`. The decay constant isA. `1.39xx10^(-11)s^(-1)`B. `13.9 xx10^(-11)s^(-1)`C. `139xx10^(-11)s^(-1)`D. `0.139xx10^(-11)s^(-1)`

The number of `alpha-` particles emitted per second by `1g` of `Ra^(22

1.	The number of `alpha-` particles emitted per second by `1g` of `Ra^(226)` is `3.7 xx 10^(10)`. The decay constant isA. `1.39xx10^(-11)s^(-1)`B. `13.9 xx10^(-11)s^(-1)`C. `139xx10^(-11)s^(-1)`D. `0.139xx10^(-11)s^(-1)`
Answer» Correct Answer - A `(Number of at oms d i s i ntegrati ng per se c o nd )/(Total n umber of at oms present)=K` or `(3.7xx10^(10))/((6.02xx10^(23))/(226))=(226xx3.7xx10^(10))/(6.02xx10^(23))=K`

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The number of `alpha-` particles emitted per second by `1g` of `Ra^(226)` is `3.7 xx 10^(10)`. The decay constant isA. `1.39xx10^(-11)s^(-1)`B. `13.9 xx10^(-11)s^(-1)`C. `139xx10^(-11)s^(-1)`D. `0.139xx10^(-11)s^(-1)`

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