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The number of neutrons in the parent nucleus which gives `N^(14) " on " beta-`emission and the parent nucleus isA. `8, C^(14)`B. `6, C^(12)`C. `4, C^(13)`D. None of these |
Answer» Correct Answer - A `._(6)C^(14) rarr ._(7)N^(14) + ._(+1)e^(0)` No. of neutrons in `C^(14) = 14 - 6 = 8` |
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