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The number of zeroes coming immediately after the decimal point in the value of `(0.2)^25` is : Given `log_10 2 = 0.30103`)A. 16B. 17C. 18D. none of these |
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Answer» Correct Answer - B Let `x = (0.2)^(25)`. Then, `"log"_(10)x = 25 "log"_(10)0.2` `rArr "log"_(10) x = 25 ("log"_(10) 2-1)` `rArr "log"_(10) = 25 xx 0.30103 - 25 = -18 + 0.52575` Hence, there are 17 zeros immediately after the decimal point. |
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