The objects at rest suddenly explodes into three parts with the mass ratio 2:1:1. The parts of equal masses moves at right angles to each other with equal speeds. The speed of the third part after the explosion will be

The objects at rest suddenly explodes into three parts with the mass r

1.	The objects at rest suddenly explodes into three parts with the mass ratio 2:1:1. The parts of equal masses moves at right angles to each other with equal speeds. The speed of the third part after the explosion will be
Answer» 2v `v/sqrt2` `v/2` `SQRT2V` SOLUTION :Resultant momentum of two part of EQUAL MASS `p_(1)=SQRT((mv)^(2)+(mv)^(2))=sqrt2mv` ut `v^1 `= speed of third part of mass 2 m Acc. to Law of conservation of momentum `(2 cancel(m)) v^(1)=sqrt2 cancel(m) v` `v^(1)=(sqrt2v)/(2)=v/sqrt2`.