

InterviewSolution
Saved Bookmarks
1. |
The orbital angular momentum of an electron in `2s`-orbital isA. `+1/2. h/(2pi)`B. ZeroC. `h/(2pi)`D. `sqrt2. h/(2pi)` |
Answer» Correct Answer - B The expression of orbital angular momentum is `L=sqrt(l(1+1)(h//2pi))` For 2s orbital , l=0 , Hence , l=0 |
|