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The osmotic pressure of a solution contaiining 1.0 g protenin in 200 mL of aqueous solution at `27^(@)C` has been found to be `2.0xx10^(-1)`atm. Calculate the molecular mass of protein. (R=0.82 L atm `mol^(-1)`).

Answer» Correct Answer - 6`15.7 g 1mol^(-1)`
`W_(B)=1.0g, V=200mL=0.2 L, T=273^(@)C=27+273=300K, pi=2.0xx10^(-1)atm`
`R=0.082" L atm mol"^(-1)K^(-1),M_(B)=?`
`M_(B)=(W_(B)xxRxxT)/(pixxV)=((1g)xx(0.082" L atm K"^(-1)mol^(-1))xx(300K))/((2xx10^(-1)atm)xx(0.2L))=615.7" g mol"^(-1)`.


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