1.

The osmotic pressure of a solution containing `40 g` of solute `("molecular mass 246")` per litre at `27^(@)C` is `(R=0.0822 atm L mol^(-1))`A. `3.0 atm`B. `4.0 atm`C. `2.0 atm`D. `1.0 atm`

Answer» Correct Answer - B
`pi=CRT=((W_(2)/(Mw_(2)))RT)/V`
Given`W_(2)=40 g`
`Mw_(2) = 246`
`T=27^(@)C = 300 K`
`V= 1 L`
Substituting all the values , we get
`pi=(40/246 )xx 0.082 xx 300 =4 atm`


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