InterviewSolution
Saved Bookmarks
| 1. |
The osmotic pressure of a solution was found to be `8 atm` when `8 mol ` of a non-volatile solute was dissolved in `V` L of solution at `300 K`.Calculate the volume of solution `(R=0.0821 L-"atm" K^(-1) "mol"^(-1))` |
|
Answer» The given values are `pi=8 atm`,`T=300K`,`n_(B)=8` `R=0.0821 L-"atm mol"^(-1)` Now,using formula `V=(nRT)/(pi)=(8xx0.0821xx300)/8 =246.3 L` |
|