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The pendulum shown in the figure is kept horizontal. It is released from this positions. What is its velocity when it reaches the lowest position? (g=9.8ms^(-2)) |
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Answer» = potential energy at position A `(1)/(2)mv_(max)^(2)=mgh` `therefore v_(max)^(2)=2gh` `therefore v_(max)=sqrt(2gh)` `therefore` Maximum velocity of PENDULUM, `v_(max)=sqrt(2xx9.8xx2.5)` `=sqrt(49)` `=7ms^(-1)` |
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