1.

The percentage of quantity of a radioactive material that remains after 5 half-lives will be .A. `1%`B. `3%`C. `5%`D. `20%`

Answer» Correct Answer - B
`N = N_(0) ((1)/(2))^(n) = N_(0)((1)/(2))^(5) = (N_(0))/(32)`
`(N)/(N_(0)) xx 100 = (100)/(32) ~~ 3%`


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