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The percentage of quantity of a radioactive material that remains after 5 half-lives will be .A. `0.3%`B. 0.01C. 0.31D. `3.125%` |
Answer» Correct Answer - D (d) Fraction of atoms remains after five half lives `(N)/(N_0) = ((1)/(2))^(t//T) = ((1)/(2))^(5T//T) = (1)/(32)` rArr Percentage atom remains `= (1)/(32) xx 100 = 3.125 %`. |
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