InterviewSolution
Saved Bookmarks
| 1. |
The perimeter of a rectangle is 160 m and the difference of two sides is 48 m. Find the side of a square whose area is equal to the area of this rectangle.1). 32 m2). 8 m3). 4 m4). 16 m |
|
Answer» Let the length and WIDTH of the given rectangle be l and b respectively. We know that, perimeter of rectangle = 2 × (length + width) ⇒ 160 = 2 × (l + b) ⇒ l + b = 80 m …(1) Given, difference of two sides = 48 m ∴ l – b = 48 …(2) SOLVING above two EQUATIONS we get, l = 64 meters & b = 16 meters We know that, Area of rectangle = l × b Let the side of the square be ‘a’ meters. Thus, according to the question ⇒ a2 = l × b [?Area of square = side2] ⇒ a2 = 64 × 16 ⇒ a = 32 meters |
|