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The photons of light having a wavelength `4000 Å` are necessary to provide `1.00 J` of energy are. |
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Answer» Energy of one photon `=hv=h.(c)/lamda` `=((6.62xx10^(-34))(3.0xx10^(8)))/(4000xx10^(-10))` `=4.965xx10^(-19)J` Number of photons `=(1.00)/(4.965xx10^(-19))=2.01xx10^(18)`. |
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