1.

The plates of a `50(mu)F` capacitor charged to `400(mu)C` are connected through a resistance of `1.0k(Omega)`. Find the charge remaining on the capacitor 1s after the connection is made.

Answer» `q_(1) = 400 muC, C = 50muF`
`R = 1000Omega, tau = RC = 50xx10^(10)xx1000= 5xx10^(-2)s`
`q = q_(0)e^(-t//tau) = 400e^((1)/(5xx10^(-2))) = (400)/(e^(+20))muC`


Discussion

No Comment Found

Related InterviewSolutions