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The plates of a `50(mu)F` capacitor charged to `400(mu)C` are connected through a resistance of `1.0k(Omega)`. Find the charge remaining on the capacitor 1s after the connection is made. |
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Answer» `q_(1) = 400 muC, C = 50muF` `R = 1000Omega, tau = RC = 50xx10^(10)xx1000= 5xx10^(-2)s` `q = q_(0)e^(-t//tau) = 400e^((1)/(5xx10^(-2))) = (400)/(e^(+20))muC` |
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