InterviewSolution
Saved Bookmarks
| 1. |
The points (–4, 0), (0, 0), (0, 3) are the vertices of a\xa0* |
| Answer» Let the points A(-4,0),B(4,0)and C(0,3)are the vertices\xa0∴AB=√(4−(−4))2+(0−0)2\u200b=√(8)2\u200b=√64\u200b=8∴BC=√(0−4)2+(0−3)2\u200b= √16+9\u200b = √25 \u200b= 5∴CA=√(−4−0)2+(0−3)2\u200b=√16+9\u200b=√25\u200b=5As we know that two points are equal in the given vertices\xa0∴This is the vertices of a isosceles triangle. | |