1.

The points A (3, 0), B (4, 5) and C (6, 7) are collinear.(a) True(b) FalseThe question was posed to me in examination.This intriguing question comes from Geometry topic in division Coordinate Geometry of Mathematics – Class 10

Answer»

The correct option is (b) False

Best explanation: We KNOW that, area of triangle = \(\FRAC {1}{2}\){x1 (y2 – Y3 ) + X2 (y3 – y1 ) + x3 (y1 – y2 )}

Let us assume the vertices of the triangle are A (3, 0), B (4, 5) and C (6, 7)

The area of triangle = \(\frac {1}{2}\) {3(5 – 7) + 4(7 – 0) + 6(0 – 5)} = \(\frac {1}{2}\) {-8} = – 4 units

Since, the area of triangle is not zero.

Therefore, the points are not collinear.



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