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The power radiated by a black body is P, and it radiates maximum energy around the wavelength λ0. If the temperature of the black body is now changed so that it radiates maximum energy around a wavelength 3λ0 / 4, the power radiated by it will increase by a factor of (a) 4/3 (b) 16/9 (c) 64/27 (d) 256/81 |
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Answer» Correct answer is: (d) 256/81 Let T0 = initial temperature of the black body. ∴ λ0T0 = b (constant) Power radiated = P0 = c. T04 (c = constant) Let T = new temperature of black body. ∴ 3λ0/4 T = b = λ0T0 or T = 4T0/3. Power radiated = c. T4 = (c T04) (4/3)4 = P0 (256/81). |
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