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The product of two rational numbers is \(\frac{-16}{9}.\) If one of the numbers is \(\frac{-4}{3},\) find the other. |
Answer» Product of two rational numbers = \(\frac{-16}{9}\) One rational number = \(\frac{-4}{3}\) Let the other rational number = x Now, According to the question, \(\frac{-4}{3}\times \text{x} = \frac{-16}{9}\) \(\) \(\Rightarrow\) \(\text{x} =\frac{-16}{9}\div\frac{-4}{3}\) \(\Rightarrow\) \(\text{x}=\frac{-16}{9}\times\frac{3}{-4}\) \(\Rightarrow\) \(\text{x}=\frac{-16\times3}{9\times-4}\) \(\Rightarrow \) \(\text{x}=\frac{-48\times-1}{-36\times-1}=\frac{48}{36}\) \(\Rightarrow \) \(\text{x}=\frac{48}{36}=\frac{48\div12}{36\div12}=\frac{4}{3}\) Hence, the other rational number is \(\frac{4}{3}\) |
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